The model is the same as for Experiment 4 with the external blind, except for the following:
The difference with previously submitted results for Experiment 5 is that there is a shift of 1 hour
 in the data following an observed experimental error.
1. It is an explicit model of the blind in the sense that there is a separate
zone for the ventilated gap between the glazing and the blind.
2. New climate and internal temp/gain data:
  Create tdf file:
  Use 6min climate data for period 8 June - 2 July (159-183) but 
  repeat 1st day (i.e. data is from 7 June to 2 July). csv data in 
  climate.csv. Simulations to run 8 June to 2 July with 1 day start-up.
  For cell data - use hourly data supplied and copy the first day. Then 
  run the hour_to_subhour program to copy each hour 10 times for 6 
  minutely data. csv data in Exp5_temps_intgains.csv
3.Alter geometry - 16cm airgap (note the opening gap to the cell is less).
  Make outer zone with the glazing unit and the surface between zones 
  as the blind material (same thermophysical properties as the external 
  blind; optical properties as given. All direct solar to internal blind.
4.Air flow network - assume openings at top and bottom of blind zone 
  connected to cell. Assume opening area is 0.15m2 (uncertain from diagram). 
  Then with two connections will get buoyant flow (but check on temperatures 
  between internal blind and the window. Also a very small crack linked to 
  outside to allow network to solve (flow results show this to have insignificnat effect).
5.Assume blind properties at all angles are same as at 90deg. Is this true?
6.Assume buoyancy correlations for all surfaces, particularly the blind.
7.Assume blind cond = 0.9 and thickness is 1mm (as in Energy+ description).
  Assume blind emissivity is 0.81 (i.e. 0.9-(1-openness factor for blind))
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Pity air temp between blind and glass was not measured as a check.
 
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Internal convection:
This model has buoyancy conv coeffs. This may be more appropriate for
conditions where we have solar radiation entering and greater differences
between surface and air temperatures.

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Shading and insolation:

No shading 
Assume insolation distribution is diffuse in cell.

Assume no shading onto opaque wall
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Results recovery
To get solar incident on south wall, extract solar absorbed (solar.grt)
 - then divide by the area of 4.831m2 and by the absorptivity of 0.23.
All straightforward except conv htc.
Extract convective flux, surface and air temperatures. Then calc htc as:
hc = Q / (Area *(Ts-Tair)) - and take absolute value
Areas used:
 southwall 4.831 m2
 glazing   1.661
 westwall 10.917
 northwall 6.608
 eastwall 10.917
 top      13.452
 base     13.452
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